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Geometry & anglesStructured · 4 marks

Triangle PQR has PQ = PR and angle QPR = 80°. Point S lies on QR such that QS = QP.

  1. Find angle QPS.
  2. Find angle PSR.
Need a hint?

Look for two equal sides first. In triangle PQS, which two angles are equal, and what does the straight line QR tell you about angle PSR?

Worked answer

  1. Triangle PQR is isosceles with PQ = PR, so angle PQR = (180° − 80°) ÷ 2 = 50°.
  2. In triangle PQS, QS = QP, so it is isosceles with equal base angles at P and S.
  3. Angle PQS = 50°, so angle QPS = (180° − 50°) ÷ 2 = 65°.
  4. Angle QSP = 65° as well, so angle PSR = 180° − 65° = 115°.
Answer: 115 °

The mistake this question tests

Habit

Angle facts (straight line, triangle, quadrilateral)

Pupils subtract the base angle at Q from 180° to get 130°, forgetting that the angle at S is equal to angle QPS, not angle PQS.

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