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AlgebraShort answer · 2 marks

Ravi wanted to buy 8 notebooks but was short of $5.40. In the end, he bought 6 notebooks and had $3.00 left. How much money did Ravi have at first?

Need a hint?

Compare the two situations: how much extra did he need for 2 more notebooks, and how much money is that in total?

Worked answer

  1. Two notebooks' cost is the gap between the two situations: 8 notebooks minus 6 notebooks, which is 2 notebooks.
  2. The money gap between the two situations is $5.40 + $3.00 = $8.40, so 2 notebooks cost $8.40.
  3. One notebook costs $8.40 ÷ 2 = $4.20.
  4. 8 notebooks cost 8 × $4.20 = $33.60, and Ravi was $5.40 short of that, so he had $33.60 − $5.40 = $28.20 at first.
Answer: $28.20

The mistake this question tests

Habit

Calculation slip

Pupils work out the cost of 8 notebooks ($33.60) and forget to take away the $5.40 shortage, or they add the shortage instead of subtracting it.

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