Knowbotic
RateStructured · 3 marks

At a bubble-tea stall, two pumps fill an empty rectangular drink dispenser U and an empty cubical drink dispenser V. All the pumped drink stays in the dispensers. Dispenser U measures 24 cm by 50 cm by 100 cm, while each inner side of V measures 40 cm. Pump R is switched on at 10 15 and fills U at 9 litres per minute. After 4 minutes, pump S is switched on and fills V at 8 litres per minute. Both pumps are stopped together. When pump R is stopped, dispenser U is 34 full.

  1. Find the volume of drink in U, in litres, when pump R is stopped.
  2. Find the number of minutes for which pump S was switched on.
  3. Find the depth of the drink in V, in centimetres, when both pumps are stopped.
Need a hint?

Use the 34-full dispenser U to work out how long R ran. Then account for the delay before using S's rate to find the amount of drink in V.

Worked answer

  1. Volume of U = 24 × 50 × 100 = 120 000 cubic centimetres = 120 litres.
  2. Drink in U = 120 × 34 = 90 litres.
  3. Pump R ran for 90 ÷ 9 = 10 minutes.
  4. Pump S ran for 10 − 4 = 6 minutes.
  5. Drink pumped into V = 6 × 8 = 48 litres.
  6. Capacity of V = 40 × 40 × 40 = 64 000 cubic centimetres = 64 litres.
  7. Fraction of V filled = 48 ÷ 64 = 34.
  8. Depth of drink = 34 × 40 = 30 cm.
Answer: 30 cm

The mistake this question tests

Habit

Minutes and hours in rate

The usual wrong path is to ignore the 4-minute delay, which makes S run for too long. Some pupils also treat the amount pumped into V as a full cubical dispenser instead of finding its depth.

How to fix it at home →

Wrong answers children often give:

  • 48 Left out the units
  • 50 Minutes and hours in rate

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